# Farmer108

yes

### Could somebody explain FE calcs to me

Wait, spotted my own mistake, that would have to be

40= (x*200)*(x*-40)

If I've worked this out correctly, x=25%, is that right?

### Could somebody explain FE calcs to me

Wait, spotted my own mistake, that would have to be

40= (x*200)*(x*-40)

### Could somebody explain FE calcs to me

Ok so using the following

0= (x+200) + (1-x) * (25%*380-75%*180)

I simplify down to

0 = (x+200) + (1-x)* -40

Which I now write as

0 = (x+2...

### Could somebody explain FE calcs to me

Yes, that's correct
But just for practice/experience sake, I'd change the numbers a bit to see which changes have which effec...

### Could somebody explain FE calcs to me

Ok, I've tried it with some different numbers

Pot: 525
bet: 300
Eq: 40%

0=x*525+(1-x) x (330-180)

Or 0=x*525+(1-x) x 150

So to get the value...

### Could somebody explain FE calcs to me

Wait, If I'm multiplying a number by 0 it becomes 0.

Therefore (1-x) * 0 = 0

So it becomes 0= (x*200) + 0

So 0= x * 200

To get 200 to 0 I multiply it...

### Could somebody explain FE calcs to me

Ok, so we don't count our bet in the winnings, I get that now.

So I get as far as solving everything to the right of (1-x)

Leaving

0=(x*200)+( (1-x)*0 )