Mixed Games Poker Forums

According to Super System or Troutulator, on the last draw, the worst pat J is favorite against the best 1 card draw.
I would like to know how calculate that.

Someone to help?

You have the number of outs and you know how many cards are in the so you just divide first number by second.

Basically in best case scenario 2347 will have 19 outs against 689TJ. There are 43 cards left in the deck, so 19/43=0.44 or 44% that 2347 will improve. Against pat queen there will already be 22 outs and 51% chance to improve.

hello aggro friend good to see you in the forums

@nervy: thank you, can you tell me what are the math with the same scenario but still 2 draw?

@snow: hi snow, the aggro style don't work very well in this time

Well, the number of cards will be different on each street but it will be close to (1-0.44)*(1-0.44)=0.31 or 31%, if I remember how to calculate probabilities correctly.

Actually it's 1-(1-0.44)*(1-0.44)=0.69

Actually it's 1-(1-0.44)*(1-0.44)=0.69

Yes, 0.31 is for pat jack to win.

Yes, 0.31 is for pat jack to win.

so you're trying to say a J has 56%~ against a 1cd but only 31% against a 2cd?

No, a J has 56% chance against a 1cd with 1 draw to come but just 31% with 2 draws to come.

And 17% with 3 draws to come! Never thought I'd need to know that, but someone patted a dealt JT against me today.

thank you

wot is this 17%, im so used to bricking!

wot is this 17%, im so used to bricking!

The thing is you usually won't pat made 9 or T against pat hand early, so it should be more than that.

not serious